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8r^2+22r+14=0
a = 8; b = 22; c = +14;
Δ = b2-4ac
Δ = 222-4·8·14
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-6}{2*8}=\frac{-28}{16} =-1+3/4 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+6}{2*8}=\frac{-16}{16} =-1 $
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